This problem is one that I was shown to at COABE a couple of years ago that still has me bamboozled. So, I am posting it here to learn from you all strategies for success.
I see lots of these "systems of equations with images instead of variables" online and since it's not written in traditional math language, the authors get to play games with assumptions...
I see five variabls and four equations. This makes me wonder if there is a single solution. I'll come back to this ;)
I understand - I have been working on this on and off for quite some time.
all the other lines are extraneous. We are told one bear is 3 zebras and asked how many bears would be equivalent to six zebras.
The rest is extra stuff.
Aren't we asked how many seals plus one bear equal six zebras? Your point is a great one as too many times our students do get caught up in extraneous information.
I've tried to assign a number value to each animal. No luck yet!
Moderator, LINCS Reading and Writing CoP